Splitting Fractions (Integrals)

Click For Summary

Homework Help Overview

The discussion revolves around evaluating the integral of the expression (2 - 3x/(Sqrt.(1 - x^2))) dx, which involves concepts from calculus, specifically integration techniques.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss separating the integral into two parts and question how to proceed from there. Some suggest using trigonometric substitution, while others propose a simpler substitution involving u = 1 - x^2.

Discussion Status

There is an ongoing exploration of different substitution methods to tackle the integral. Participants have provided varying suggestions, indicating a productive exchange of ideas without reaching a consensus on the best approach.

Contextual Notes

Some participants express confusion about the initial attempts and the appropriateness of different substitution methods, highlighting the complexity of the integral involved.

FuturEngineer
Messages
10
Reaction score
0

Homework Statement


Evaluate

Integrate (2-3x/(Sqrt.(1 - x^2))) dx

Homework Equations


1/Sqrt.(1-x^2) = arctan

The Attempt at a Solution


I am so lost, but this is what I've tried, but didn't work...

I separated the integral into two so
Integral of (2/(Sqrt.(1-x^20))) dx - integral of (3x/(Sqrt.(1-x^2))) dx
I am not sure how to proceed? Help! [/B]
 
Physics news on Phys.org
this can be solved using a trig substitution for x. Can you think of what this substitution should be to simplify the denominator?
 
FuturEngineer said:

Homework Statement


Evaluate

Integrate (2-3x/(Sqrt.(1 - x^2))) dx

Homework Equations


1/Sqrt.(1-x^2) = arctan

The Attempt at a Solution


I am so lost, but this is what I've tried, but didn't work...

I separated the integral into two so
Integral of (2/(Sqrt.(1-x^20))) dx - integral of (3x/(Sqrt.(1-x^2))) dx
I am not sure how to proceed? Help! [/B]
Looks like a natural for trig substitutions for both integrals
 
I would NOT use a trig substitution for \frac{3x}{\sqrt{1- x^2}}. Instead let u= 1- x^2
 
HallsofIvy said:
I would NOT use a trig substitution for \frac{3x}{\sqrt{1- x^2}}. Instead let u= 1- x^2
A trig substitution would work, but I agree that an ordinary substitution (as you suggest) would be easier, which makes it a better choice.
 
Thanks!
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
Replies
4
Views
2K
  • · Replies 105 ·
4
Replies
105
Views
8K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 44 ·
2
Replies
44
Views
6K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K