Spring & Blocks: Max Friction Force & Oscillation

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The discussion revolves around the dynamics of two blocks, A and B, with block B oscillating on top of block A due to a spring attached to it. The key point is that the maximum static friction force between the blocks must be greater than the force exerted by the spring at maximum displacement to prevent slipping. The static friction adjusts to the applied forces, meaning it can be less than the maximum static friction value (μmg) while still allowing for oscillation. The equations of motion reveal that the frictional force acts as an internal force within the system, ensuring that both blocks can move together without slipping. Overall, the relationship between spring force and friction is crucial for understanding the oscillatory behavior of the blocks.
zorro
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I am stuck up in a situation created by me.

Consider a block A resting on a smooth horizontal surface. There is another block B of the same size/mass resting over it. There is some friction present in between them, with coefficient of friction μ. A spring of spring constant K is attached to block B (the other side attached to a wall off course) and the blocks are displaced through a distance 'x' together and released. The block B oscillates without slipping over the block A.

At the max. displacement, there should be a max. value of the friction force. Now is this value of friction force equal to μmg? If we draw a F.B.D. of block B at max. displacement, we find that Kx should be greater than friction force for the block to oscillate. If the max. value is μmg, and Kx>μmg, then why doesn't the block B slip over the block A?
 
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if kx exceeds μmg, there will be slipping and relative motion between the blocks. The frictional force at max displacement has to be less than μmg, only then the blocks will oscillate together without slipping.
Reason: The frictional force is STATIC and not DYNAMIC. Static friction adjusts itself with the amount of force applied on the body. So μmg (where μ is coefficient of static friction) can be a quantity which is greater than Kx (where x is the maximum displacement). If even the extreme value of Kx is less than μmg, then the two bodies never slip against each other.

suppose frictional force is f between the blocks and at maximum displacement,
f(max) = kx (x is maximum at maximum displacement)

f(max) < μmg (for the bodies to never slip)
 
androidx219 said:
f(max) = kx (x is maximum at maximum displacement)

If f(max)=kx, how do you think will the block return to its mean position and perform oscillations?
 
I am sorry, I was grossly wrong at the statement I made there. Thanks for pointing that out and correcting me. f(max) can never be equal to kx and will always be less than kx, otherwise the blocks wouldn't move at all as you rightly said.

Lets consider the FBDs of A and B separately,

suppose at anypoint say, the combined acceleration is a, then
K.x - f = m.a (for B)
f= m.a (for A)

so k.x = 2m.a

so when considering A and B as a combined body together, f comes out to be a mere inernal force for this system. This should make things a bit clearer to both of us.
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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