Spring force and the force of friction

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The discussion revolves around a misunderstanding of mass representation in a physics assignment related to spring force and friction. The user is confused about why the mass (m) is canceled out in the equations, believing it represents different masses for two boxes. The clarification provided indicates that the same mass (m) applies to both boxes, allowing them to accelerate together due to sufficient friction. This understanding is crucial for solving the assignment correctly. The conversation highlights the importance of recognizing the context of mass in physics problems.
curicuri
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Homework Statement
A box with a mass of 20 kg is put on a vertical table that is is free from friction. On top of that box is another box with the mass of 2 kg. The friction number between the boxes are 0,35. The big box that lays on the table has a spring attached to it, that has the "spring-constant"=400N/m. The spring is attached to the wall on the other end.
Determine max amplitude that can be obtained without the small box falling off.
Relevant Equations
Ff=Fr
Hello, do someone have time to help me out with an assignment?

My question
In the answer sheet they say:
244937

What I do not understand is why m is withdrawn from both sides, since I don't see that those represent the same mass. When I did the assignment I thought m at the left side would be the mass of the small box, and m at the right side would be the mass of the big box. That was why I did not cancel m out, which was why I got the wrong answer.
 
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You want to know that the friction between the boxes is large enough to accelerate the small box with the same acceleration. So ##m## is the small box on both sides.
 
AA of course, thank you :)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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