Spring forces / Deflection of springs of members

Click For Summary
SUMMARY

The discussion centers on solving a mechanics problem involving a hydraulic cylinder and spring deflections in a truck's brake linkage system. The hydraulic cylinder AB exerts a tensile force of 12 kips, necessitating the calculation of deflection (d) and forces in members AC, AE, and AG. The participant utilized free body diagrams and equilibrium equations to analyze the system, specifically focusing on the sum of forces in both the x and y directions. The approach is correct, as it adheres to fundamental mechanics principles, allowing for the derivation of equations to solve for the unknown forces.

PREREQUISITES
  • Understanding of static equilibrium in mechanics
  • Familiarity with free body diagrams
  • Knowledge of Hooke's Law (F = kd)
  • Basic principles of hydraulic systems
NEXT STEPS
  • Study the application of free body diagrams in complex systems
  • Learn advanced techniques for solving static equilibrium problems
  • Explore the principles of hydraulic force transmission
  • Investigate the effects of spring constants on deflection in mechanical systems
USEFUL FOR

Mechanical engineers, students studying statics and dynamics, and professionals involved in the design of hydraulic systems and spring mechanisms will benefit from this discussion.

RelicJ
Messages
1
Reaction score
0

Homework Statement



The brake linkage for a truck is actuated by hydraulic cylinder AB. Cylinder AB, springs CD, EF, and GH are the slotted tracks are all horizontal. The slotted tracks are frictionless. If the cylinder AB exerts a tensile force of 12 kips, determine the deflection d and the forces in members AC, AE, and AG.

The photograph of the situation given is below, along with my attempt with free body diagrams.

Homework Equations


F = kd (spring equation)

The Attempt at a Solution



I was unsure where to really start, but my teacher did give us a few clues. I broke the problem into 4 different free body diagrams which I have attached and I figured out multiple equations using equilibrium equations like sums of forces in the x and y direction. I am unsure where to go from here... if this is even correct.
 

Attachments

  • rsz_problem.jpg
    rsz_problem.jpg
    24.8 KB · Views: 549
  • FBD.jpg
    FBD.jpg
    15.8 KB · Views: 1,174
Physics news on Phys.org
Once the brakes are operated and everything has stopped moving the forces on various points sum to zero. For example on point G in the horizontal direction you can write..

FAGCos(45) + FGH = 0

You can write other similar equations for other points in your diagrams including one for point A.

You also know that points CE and G all move the same distance.

Should be possible to write enough equations to solve for the unknowns.
 

Similar threads

Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
25
Views
9K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K