Spring with friction (nonconservative force)?

AI Thread Summary
A 5 kg mass slides on a surface with a friction coefficient of 0.48 and compresses a spring with a spring constant of 138 N/m after reaching a speed of 7 m/s. The discussion revolves around calculating the compressed distance (d) of the spring while considering the work done by nonconservative forces, particularly friction. Participants emphasize the importance of correctly applying energy conservation principles and managing signs in equations, especially regarding the frictional force. The final energy equation derived is 0 = 1/2kd^2 + Ffrd - 1/2mvi^2, leading to a quadratic solution for d. The conversation highlights the complexities of incorporating nonconservative forces in energy calculations.
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Homework Statement


A 5 kg mass slides to the right on a surface having a coefficient of friction 0.48. The mass has a speed of 7 m/s when contact is made with a spring that has a spring constant 138 N/m. The mass comes to rest after the spring has been compressed a distance d. The mass is then forced toward the left by the spring and continues to move in that direction beyond the unstretched position. Finally the mass comes to rest a distance D to the left of the unstretched spring. The acceleration of gravity is 9.8 m/s2. Find the compressed distance d.


Homework Equations



Wnet = WC + WNC

WNC = Ffrdcos\theta

\SigmaEbefore = \SigmaEafter + WNC

The Attempt at a Solution



I'm just not sure if I should separate this into two parts where I find the the final energy just before it touches the spring and then the second part, find the distance with the final energy found in part one?

And I'm really confused as to incorporating the nonconservative force in this equation. I've looked at my book and there is no example of this or anything =( They only have it in relation to potential energy in the y-direction.
 
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hint: What is the kinetic energy of the mass when the spring is compressed a distance d?

hint: What is θ?

caution: Be careful about minus signs. They are arbitrary, but you should assign them consistently. Work done on the mass should have an opposite intrinsic sign to work done by the mass. This is in addition to the sign that you calcuate from cosθ.
 
KE (when compressed) = 1/2mvf2 + 1/2kd2 - Ffrd

\theta = 180

Right track??
 
I figured it out! Thank you so much!

1/2mvi2= 1/2kd2 + Ffrd

0 = 1/2kd2 + Ffrd - 1/2mvi2

solve with quadratic ...

(I was getting stumped on that sign for the frictional force... I think that's what you were hinting at and I just wasn't putting 2 and 2 together!)
 
I'm sorry, I wasn't online this evening. Yes, that looks correct. (Of course, you still need to determine Ffr, but I suppose you know how to do that.) Good job.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
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