Square Inscribed in a Square: Maximizing Distance Between Vertices

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To determine the greatest distance between a vertex of a square inscribed in another square, one must consider the dimensions of both squares. The inner square has a perimeter of 20, giving it a side length of 5, while the outer square, with a perimeter of 28, has a side length of 7. The maximum distance between a vertex of the inner square and a vertex of the outer square occurs when the inner square is positioned diagonally within the outer square. The discussion clarifies that an inscribed square typically touches the sides of the outer square at its vertices, rather than along the base. Understanding these geometric relationships is crucial for solving the problem effectively.
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Homework Statement



A square of perimeter 20 is inscribed in a square of perimeter 28. What is the greatest distance between a vertex of the inner square and a vertex of the outer square.

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The Attempt at a Solution

I have a question. Can a square be inscribed in another square by having it sit along the base and the side of the bigger square? Does it only have to touch vertice to side?
 
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I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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