Stability of Carbocation: The Impact of +I Effect

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The +I effect can stabilize a carbocation by increasing electron density, which helps neutralize the positive charge. However, this stabilization may come at the cost of altering the carbocation's nature, potentially leading to instability. Inductive and mesomeric effects, such as +I and +M, further contribute to the stabilization of carbocations by reducing their electron deficiency. The balance between stabilization and the preservation of the carbocation's characteristics is crucial in understanding its overall stability. Ultimately, the +I effect plays a complex role in carbocation stability.
nishanth R
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Homework Statement


Does +I effect stabilize or destabilize a carbocation

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The Attempt at a Solution


In one way, +I effect tends to increase electron density on the carbocation and hence neutralize the charge and hence would stabilize it. On the other hand, the nature of carbocation would be lost( I don't know whether that is related to unstability)
 
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inductive and mesomer effects(+I , +M) stabilize carbocation because they decrease carbocation's electron deficiency
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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