Engineering Stable Load Current and Voltage in a Simple MOSFET Driver Circuit

Click For Summary
The discussion focuses on modeling the load voltage in a MOSFET driver circuit, specifically addressing an intended load voltage of 18V and the behavior of the circuit under different conditions. When the switch is on, the load voltage is expected to be around 48V minus the FET voltage drop, with the load current remaining approximately at 1A due to high inductance and frequency. The load current will alternate between the diode and the FET, causing the load voltage to fluctuate between two levels. The relationship between the rise and fall of current is governed by the equation VL = L · di / dt, emphasizing the need for balance in current changes. The discussion also raises questions about the duty cycle and the average voltage across the load, indicating the complexity of the circuit's behavior.
Forcefedglas
Messages
26
Reaction score
0

Homework Statement


gnburu0.png

Homework Equations

The Attempt at a Solution


I know what the transients should generally look like, the only part that's throwing me off is how to model the intended load voltage of 18V. I'm guessing that when the switch is on (after transients) the load voltage will be close to 48V (minus the FET voltage drop) since there's nothing in place regulating it, is it safe to assume that the load current stays at 1A in this case? And if the FET is off (after transients), the flyback diode will be forward biased and the voltage across the load will be -0.46V? If that's the case, what's the effect of the 'intended' load voltage if any?

Thanks in advance.
 

Attachments

  • gnburu0.png
    gnburu0.png
    30.8 KB · Views: 1,069
Last edited:
Physics news on Phys.org
Forcefedglas said:
I'm guessing that when the switch is on (after transients) the load voltage will be close to 48V (minus the FET voltage drop) since there's nothing in place regulating it, is it safe to assume that the load current stays at 1A in this case?
Inductor current will remain very close to 1 amp because inductance is large and frequency is high at 1MHz.

The load current will switch between the diode and the FET. Load voltage will change between two values.
While the FET is on the load current will rise slowly, while the diode is on current will fall slowly.
Relevant equation? VL = L · di / dt
For a stable current, Irise must equal Ifall.

What will the duty cycle be?
What will the average voltage across the load be?
 

Similar threads

Replies
15
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 42 ·
2
Replies
42
Views
5K
  • · Replies 12 ·
Replies
12
Views
12K