(a) Calculate the size of Conductor and Fuse, the amount of Current through the conductor, Voltage ACROSS the existing LOAD and power consumed by the EXISTING LOAD under normal circuit condition (when the switch of the above circuit will be closed). (b) Calculate the overload current, voltage and power if additional two 30 OHMS loads are connected in parallel across the existing load. (When the switch will be closed). (c) Calculate the short circuit current, voltage and power if the LOAD is shorted. (When the switch will be closed). (d) What will happen to this circuit if HOT” CONDUCTOR COMES IN CONTACT WITH METAL RACEWAY OR OTHER METAL OBJECT. (e) What will happen to this circuit under open circuit condition? Calculate the open circuit current, voltage and power if one 30 OHMS load IS connected across the existing load under this open circuit condition? (When the switch will not be closed). 2. Relevant equations I = E/R 3. The attempt at a solution I know: 240 = 7.992 or 8amps. 24 + 0.001 + 0.001 + 0.001 How do i figure out fuse size and voltage? i know this is very basic... Any help is greatly appreciated.