Standard Deviation of test scores

AI Thread Summary
The discussion focuses on calculating the population standard deviation of a class's mathematics test scores. Participants clarify the difference between biased and unbiased standard deviation formulas, emphasizing the importance of correctly applying the formulas based on the data set size. The mean score is calculated as approximately 79.45, with standard deviations found to be around 5.57 (unbiased) and 5.44 (biased). A participant realizes their earlier miscalculation stemmed from not multiplying the squared differences by the number of occurrences for each score. The conversation concludes with an acknowledgment of the correction and understanding of the calculations involved.
priscilla98
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Homework Statement



The scores of one class on the Unite 2 mathematics test are shown in the table below. Find the population standard deviation of these scores, to the nearest tenth.

Unit 2 Mathematics Test

Score - Number of people

96 - 1
92 - 2
84 - 5
80 - 3
76 - 6
72 - 3
68 - 2

Homework Equations



standard deviation formula

The Attempt at a Solution



I used this website to find the standard deviation for this problem. But my answer is higher than a 100 and i think i made some miscalculations.
http://www.gcseguide.co.uk/standard_deviation.htm
 
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What you are calculating is unbiased standard deviation. I think you have been asked to calculate biased SD for which the formula is

\sigma^2 = \overline{(x - \overline{x})^2}

For large data sets, you do not have much issues with the two formulae. This difference in formulae is based on biased/unbiased estimators.
 
You have to find the mean of the scores first. What did you get?

ehild
 
The mean is 79.8095.
 
Wouldn't you have to subtract the mean from the test scores?
 
Yes, and take the square and the sum of squares. What did you get?

ehild
 
in my understanding (please correct if wrong):

mean = (96*1+92*2+84*5+80*3+76*6+72*3+68*2)/sum(people) = 79.45

std deviation = sqrt( sum((score(i)-mean)^2) / (sum(people) - 1)) = 5.57 unbiased
= sqrt( sum((score(i)-mean)^2) / (sum(people))) = 5.44 biased
 
The mean is correct, but I got 7.54 and 7.36 for the standard deviations.

ehild
 
ehild:
Grateful if you could share the formula please. I am still learning this stuff...
 
  • #10
Your formula is correct. Are you sure you did not make any mistake in the calculation? Did you multiplied the squares with the number they occur? I guess you did not. You have to sum for all people.

ehild
 
Last edited:
  • #11
now I see, indeed haven't multiplied differences squared by number of people. It's the same as your result now.

Thank you!
 
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