Standing Wave Question: Wavelength of Resultant Wave with Two Opposing Waves

AI Thread Summary
A standing wave formed by two identical waves traveling in opposite directions retains the same wavelength as the original waves. The nodes and antinodes of the standing wave remain fixed, confirming this relationship. The mathematical representation of the superposition of the two waves supports this conclusion, as it simplifies to a function with the same wavelength. Visual aids, such as drawings, can further clarify this concept. Thus, the wavelength of the resultant standing wave is indeed the same as that of the original waves.
vivekfan
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Homework Statement



If a standing wave is produced by two identical waves traveling in opposite directions, is the wavelength of the resultant wave simply the wavelength of the original wave?


Homework Equations



ysin(kx)cos (wt)

The Attempt at a Solution



I'm pretty sure it produces a wavelength of the original wave because A standing wave requires that the nodes and antinodes remain in the same place, but I want to make sure. Please help!
 
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sinA + sinB == 2sin((A+B)/2)cos((A-B)/2)

so a sin(kx - wt) + a sin(kx + wt) = 2a sin(kx)cos(wt)

k is 2pi/wavelength.

Any help?
 
davieddy said:
sinA + sinB == 2sin((A+B)/2)cos((A-B)/2)

so a sin(kx - wt) + a sin(kx + wt) = 2a sin(kx)cos(wt)

k is 2pi/wavelength.

Any help?

Does that mean that the standing wave has the same wavelength as the original?
 
vivekfan said:
Does that mean that the standing wave has the same wavelength as the original?

I think so.
Try drawing some pictures.
 
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