Stat mech: Fermi-Dirac distribution

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SUMMARY

The discussion centers on the Fermi-Dirac (FD) distribution and its interpretation as the probability of occupancy for quantum states. A participant presents an alternative approach using the partition function Z_i to derive the probability P(1) for a fermionic state, leading to a different expression than the standard FD distribution. The key equation discussed is P(1) = e^β(μ-ε_i) / Z_i, which raises questions about its equivalence to the FD distribution. The conversation also explores the implications of manipulating the numerator and denominator of this expression.

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davon806
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Homework Statement


Show that the FD distribution can be viewed as giving the probability that a given state ( of the prescribed
energy) is occupied.

Homework Equations

The Attempt at a Solution


Solution to this problem:
Q.jpg


I understand the solution,but I took a different approach which gave a different answer.

For a quantum state i,denote Z_i as its partition function.Then for a single state distribution(2nd red box) :
F.jpg


For a fermion,n_i = 0 or 1. I want to find P(1) for the state i,so by the 2nd box it is P(1) = e^β(μ-ε_i) / Z_i , which is not the same as the FD distribution?
 
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davon806 said:
For a fermion,n_i = 0 or 1. I want to find P(1) for the state i,so by the 2nd box it is P(1) = e^β(μ-ε_i) / Z_i , which is not the same as the FD distribution?
What happens if you multiply the numerator and the denominator by ##e^{-\beta (\mu - \epsilon)}##?
 
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