Static friction and acceleration

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Homework Help Overview

The problem involves a glass of orange juice on the floor of a subway car that is accelerating. The focus is on determining the maximum acceleration of the subway car that prevents the juice from sliding backward, given the coefficient of static friction.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between static friction and normal force, questioning how to approach the problem without a specific mass for the juice. Some suggest denoting the mass as a variable and exploring the implications of Newton's laws.

Discussion Status

The discussion has seen various attempts to clarify the relationship between forces and friction. Some participants have provided guidance on maintaining variables in expressions, while others have noted the need to address multiple unknowns in the problem.

Contextual Notes

There is a lack of specific mass information for the juice, which complicates the calculations. Participants are also navigating the implications of Newton's laws in the context of static friction.

goonking
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Homework Statement


A glass of orange juice is on the floor of a subway car traveling along a straight path at constant velocity. The coefficient of static friction between the glass and the floor is 0.32. The subway suddenly accelerates forward. What is the maximum acceleration that the subway car can have without the orange juice sliding backward on the floor

Homework Equations


Fs = μ FN

The Attempt at a Solution


So we want the juice to stay still. So the FN x μ cannot become equal or greater than Fs, correct? How would we approach this problem without a mass given for the juice?
 
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Denote the mass as m kg, and proceed as you have outlined.
 
NascentOxygen said:
Denote the mass as m kg, and proceed as you have outlined.
so FN = m x mg?
 
What is Newton's third law?
 
AlephNumbers said:
What is Newton's third law?
For every action, there is an equal and opposite reaction.
 
goonking said:
so FN = m x mg?
Using F = m.a you get FN = m.g
 
NascentOxygen said:
Using F = m.a you get FN = m.g
yes, so now Fs = μ mg but we still have 2 unknowns
 
goonking said:
yes, so now Fs = μ mg but we still have 2 unknowns
Proceed to determine maximum acceleration undaunted ...
 
.32 x g = .32 x 9.8 m/s^2 = 3.136, that's the answer, thanks!
 
  • #10
goonking said:
.32 x g = .32 x 9.8 m/s^2 = 3.136, that's the answer, thanks!
You should have kept the m in your expressions, and at the end shown they cancel, rather than letting them disappear without explanation.
 
  • #11
NascentOxygen said:
You should have kept the m in your expressions, and at the end shown they cancel, rather than letting them disappear without explanation.
ok, ill remember that
 

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