Static hydraulics, calculate water depth

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The discussion revolves around calculating the water depth in a tank with a steel box placed at the bottom, given a pressure of 10,000 Pa on the box's top surface. The relevant formula used is P = pgh, where water density is 1000 kg/m³ and gravity is 9.81 m/s². An initial calculation incorrectly rearranged the formula, leading to an incorrect depth. After correcting the algebra, the final water depth is determined to be 1.269 meters, which includes the height of the box. The conversation highlights the importance of accurate unit notation and careful algebraic manipulation in physics problems.
escobar147
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Homework Statement


Refer to Figure 3. A steel box (250 mm x 250 mm x 250 mm) is placed at the bottom of a tank. If the pressure on the top surface is 10000 Pa, what is the water depth in the tank?

Answer
a. 1019 mm
b. 251.02 mm
c. 1269 mm

water density: 1000 kg/m3
gravity: 9.81



Homework Equations


P=pgh








The Attempt at a Solution



if the pressure on the top surface f the box is 10,000pa, then by rearranging the formulae P=pgh you get:

10,000= 1000 x 9.81 x h

solving for h:

h = 0.981 meters

adding the depth at the top of the box to the height of the box to find the final depth of the tank=

981mm + 250mm = 1231mm

however this is not the correct answer?
 
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escobar147: You simply made an obvious algebra mistake. Try again. Also, always leave a space between a numeric value and its following unit symbol. E.g., 250 mm, not 250mm. Also, the unit symbol for pascal is Pa, not pa. Lowercase p means pico. It should be 10 000 Pa.
 
omg i have just realized my mistake. i incorrectly re-arranged the formula, the actual answer is this:

P = pgh

10,000 = 1000 x 9.81 x h

10,000 = 9810 x h

10,000/9810 = 1.01936 meters

1.01936 meters + 250 mm

= 1.269 meters.

thanks for your help nvn i appreciate it!
 

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