(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The beam is subjected to two oppositve vertical forces and one horizontal force as shown. Determine the reactions at the supports A & C

2. Relevant equations

[itex]\sum[/itex]forces in plane = 0

moment = force x perpendicular distance

3. The attempt at a solution

[itex]\sum[/itex]Y = 15 + RyC + RyA - 15 = 0

[itex]\sum[/itex]x = 20 + RxC = 0

[itex]\sum[/itex]Moments around A = (-15 * 3) + (15 *12)+(RyC * 9)

Reaction at C in x = 20 kN

Not sure about reactions in Y at either, tried to calculate this from the moments but neither of these types of joint provide any reaction force to moments?

Thanks in advance

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# Homework Help: Statics: moments around beam subjected to 3 forces

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