Calculating Reaction Forces in a Beam - Moment About Point B

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SUMMARY

The discussion focuses on calculating reaction forces in a beam, specifically addressing the moment about point B due to a uniformly distributed load (UDL) of 15 kN/m over a span of 7 meters. The correct moment calculation is established as 15 kN/m * 7 m * 5.5 m, where 5.5 m is the distance from point B to the center of the UDL. This distance is derived from the total distance of 7 m, with the center of the load located 3.5 m from either end, plus an additional 2 m from point B to the left end of the UDL.

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I am calculating the all reaction forces in this beam.
However, I want to ask:
By taking moment about point B, why does the moment of the UDL become 15*7*5.5 instead of 15*7*4.5

Thanks !
 
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feedingjax said:
t5sivs.jpg


I am calculating the all reaction forces in this beam.
However, I want to ask:
By taking moment about point B, why does the moment of the UDL become 15*7*5.5 instead of 15*7*4.5

Thanks !

It's not clear where the 4.5 is measured from in the second expression.

The UDL is a constant 15 kN/m applied over a distance of 7 meters in total, therefore, the center of this load is 3.5 meters from either the LHS or the RHS of the UDL.
By taking point B as the moment reference, the moment of the UDL becomes 15 kN/m * 7 meters * (2 + 3.5) meters, where 2 + 3.5 = 5.5 meters is the distance from point B to the center of the UDL.
 
When determining the moment of a distributed load about a point, you may find the moment by replacing the distributed load with a resultant concentrated load acting at the cg of the load distribution. Where is the cg of that load located along its 7 foot length?
 

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