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X1 Y1 Z1

0 0 0 (5 times Z1 is 0 for X1=0 and Y1=0)

0 0 0

0 0 0

0 0 0

0 0 0

0 1 0

0 1 0

0 1 0

0 1 0

0 1 0

0 1 0

0 1 0

0 1 1

0 1 1

0 1 1

0 1 1

0 1 1

0 1 1

0 1 1

0 1 1

.

.

.

Which is..

(Same table which is above..)

X1 Y1 Z1 (Count of Zeros) (Count of Ones)

0 0 5 2

0 1 7 8

1 0 0 10

1 1 5 1

X2 Y2 Z2(Count of Zeros) (Count of Ones)

0 0 10 4

0 1 14 16

1 0 0 20

1 1 10 2

Finding P(Z1|X1Y1) AND P(Z2|X2Y2)

HERE it is the same..

example

X1 Y1 Z1 (Probability of Zeros)

0 0 5|7

X2 Y2 Z2 (Probability of Zeros)

0 0 10|14

But what if this is not the case and we have

X2 Y2 Z2(Count of Zeros) (Count of Ones)

0 0 7 5

0 1 12 2

1 0 2 0

1 1 1 5

Than how to know how close is P(Z1|X1Y1) AND P(Z2|X2Y2) using some method..

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# Statistical Comparision between Conditional Probability

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