Step function Laplace transform - can someone check my work?

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The discussion focuses on verifying Laplace transforms for step functions. The first transform presented is for the function 3u(t) - 3u(t-2), resulting in 3/s - 3e^(-2s)/s. The second transform involves 5t/2u(t) - 5t/2u(t-2), yielding 5/(2s^2) - 5e^(-2s)/(2s^2). A participant expresses uncertainty about a third problem, suggesting the use of the integral definition of the Laplace transform and Euler's rule to simplify cosine factors into exponentials. The conversation emphasizes the importance of converting phase angles to radians for accurate calculations.
eehelp150
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Homework Statement


upload_2016-12-1_0-49-14.png


Homework Equations

The Attempt at a Solution


1
##3u(t)-3u(t-2)##
##\frac{3}{s}-\frac{e^{-2s}3}{s}##

2
##\frac{5t}{2}u(t)-\frac{5t}{2}u(t-2)##
##\frac{5}{2s^2}-\frac{5e^{-2s}}{2s^2}##

3
I have no idea how to do this one.
 
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eehelp150 said:
3
I have no idea how to do this one.
How about using the (integral) definition of the Laplace transform?
You can use Euler's rule to change the cosine factor to more exponentials, leaving just exponentials in the integrand, then perhaps reverse that to get the real transform.
Don't forget to change the phase angle to radians.
 

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