Still stuck on diffrential equations

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SUMMARY

The discussion focuses on solving differential equations using substitutions and finding an integrating factor. The user successfully derived expressions for dy and dx using the product rule and substitution, specifically noting that dy = udv + vdu and dx = du - udv - vdu. The next challenge involves finding an integrating factor 'mu' for the expression w = (1 - y e^(y/x+y))dx + (1 + xe^(y/x+y))dy to make it exact. The user is seeking guidance on how to derive 'mu' after substituting the values for x and y.

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sara_87
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Homework Statement



let x + y = u and y = uv
Expand dx and dy in terms of du and dv

Homework Equations





The Attempt at a Solution



i got this answer:

dy = udv + vdu

and

dx = du - udv - vdu


is this correct?
 
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Looks correct to me. Using the product rule on "y = uv", you get dy, and then a simple substitution in the equation "x + y = u" gives you dx. You got it.
 
ok thanx
now that makes things harder

we have w=(1 - y e^(y/x+y))dx + (1 + xe^(y/x+y)dy

find an integrating factor 'mu' in terms of u and v such that 'mu'w is exact

after subing that lot in for x and y and dx and dy, and rearranging a little i got this:


'mu' = [ (1+u(1-v)d'mu' ... something long and horrible!

how do i do this?
 

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