Still stuck on diffrential equations

In summary, the conversation is about expanding dx and dy in terms of du and dv, and finding an integrating factor 'mu' in terms of u and v to make 'mu'w exact. The final solution involves substituting x and y for u and v and rearranging to get 'mu'.
  • #1
sara_87
763
0

Homework Statement



let x + y = u and y = uv
Expand dx and dy in terms of du and dv

Homework Equations





The Attempt at a Solution



i got this answer:

dy = udv + vdu

and

dx = du - udv - vdu


is this correct?
 
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  • #2
Looks correct to me. Using the product rule on "y = uv", you get dy, and then a simple substitution in the equation "x + y = u" gives you dx. You got it.
 
  • #3
ok thanx
now that makes things harder

we have w=(1 - y e^(y/x+y))dx + (1 + xe^(y/x+y)dy

find an integrating factor 'mu' in terms of u and v such that 'mu'w is exact

after subing that lot in for x and y and dx and dy, and rearranging a little i got this:


'mu' = [ (1+u(1-v)d'mu' ... something long and horrible!

how do i do this?
 

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