Stochastic processes: martingales

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SUMMARY

This discussion focuses on the application of martingales in stochastic processes, specifically in the context of a gambling scenario. The gambler's winnings, denoted as Yn, are established as a martingale, and a new process Zn is introduced, defined as Zn = Yn2 - n. The Martingale Stopping Theorem is applied to show that E(ZN) = 0, leading to the conclusion that E(N) = E(YN2), where YN can only take values A or -B. The discussion emphasizes the importance of understanding stopping times in Markov Chains to compute expectations.

PREREQUISITES
  • Understanding of martingales in probability theory
  • Familiarity with stochastic processes and their properties
  • Knowledge of the Martingale Stopping Theorem
  • Basic concepts of Markov Chains and stopping times
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  • Study the Martingale Stopping Theorem in detail
  • Learn about the properties of Markov Chains and their stationary transition probabilities
  • Explore advanced topics in stochastic processes, focusing on martingales
  • Practice calculating expectations using stopping times in various stochastic scenarios
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Let Y_{n} be the gambler's winnings after n games. Clearly, Y_{n} is a martingale. We introduce a new stochastic process Z_{n}, where Z_{n}={Y_{n}}^2-n. It can be shown that Z_{n} is a martingale with respect to Y_{n}. (Can you try to show this?)

Let N be the random variable for the step where the gambler's winnings first reach A or -B. Then, we have E(Z_{N})=E({Y_{N}}^2)-E(N). By applying the Martingale Stopping Theorem (first check the necessary conditions are satisfied), we can show E(Z_{N})=0.

This leaves us with E(N)=E({Y_{N}}^2). To determine E({Y_{N}}^2), use the definition of expectation, and observe that Y_{N} can only take the values A or -B. To calculate the relevant probabilities, apply some formulae related to stopping times of Markov Chains (with stationary transition probabilities). We are now able to compute E({Y_{N}}^2), which will be equal to E(N).
 
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