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Straight line motion

  1. Mar 4, 2013 #1
    1. The problem statement, all variables and given/known data

    A 0.525kg ball starts from rest and rolls down a hill with uniform acceleration, traveling 200m during the second 10.0 s of its motion.


    2. Relevant equations

    xf= xi + vi +1/2a(t)^2
    x= vi + at


    3. The attempt at a solution

    a= 4 m/s^2

    x=50 m


    its wrong
     
    Last edited: Mar 4, 2013
  2. jcsd
  3. Mar 4, 2013 #2
    A 0.525kg ball starts from rest and rolls down a hill with uniform acceleration, traveling 200m during the second 10.0 \rm s of its motion.

    So, are you trying to solve for acceleration?
    what does this part mean, "during the second 10.0 \rm s of its motion" is it a typo?
     
  4. Mar 4, 2013 #3
    solve the distance it travels @ 5 seconds.
     
  5. Mar 4, 2013 #4
    So the question states that the ball travels during the second 10s and you are trying to find the distance after the first 5 seconds?

    Use a = 2d / t² to find acceleration where t will be your 10 seconds
    Then use the equation d = ut + ½ at² where t will be your 5 seconds and solve for distance...

    I also got x = 50.... are your units correct?

    Edit:
    Maybe it is 16.63 m? (edited again)
    a=200m/150 s² = 1.33m/s²
    d = ut + ½ at²
    d = 0 + ½ (1.33)(5)²
     
    Last edited: Mar 4, 2013
  6. Mar 4, 2013 #5
    hmmmmmm im so confused
     
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