- #1
PaulPaul
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Homework Statement
Hi. I don't understand my results when I deconvolve two non-negative peaks. I also get a peak but it is fallowed by a negative "valley". Can devonvolution of two positive graphs give graphs with negative parts?
Homework Equations
In this case I deconvole two gamma variates:
f(t) = a(t-to)^b exp[ -(t-to)/c ] step(t-t0)
g(t) = d(t-t1)^k exp[ -(t-t1)/m ] step(t-t1)
The Attempt at a Solution
I use MATLAB's discrete Fourier tranformation function and simply divide without filtering (what filter would I use? Is there noise in a sampled analytical function?) I've also tried changing sampling frequency and the window of the function = the negative dip stays there! I've also used Singular value decomposition to do the deconvolution- also I get a negative valley. Where does this come from? Does deconvoluion have a unique solution?
thanks.