Strange infinite series problem using integral test.

[erjkism]

Homework Statement

I need to show that

\Sigma\frac{1}{nlnnlnlnn}

from n=27 to n=10^(100,000)

is approximately equal to 8.1

 

[erjkism]

i did the u substitution, u =nlnn

and i get

\int\frac{1du}{u}

which just becomes [lnu]
which becomes: [ln(lnlnn)] evaluated from 27 to 10^100,000

 

[exk]

is the denominator of your summation n*ln(n)*ln(ln(n))?

 

[erjkism]

yea it is