# Strange infinite series problem using integral test.

1. Homework Statement
I need to show that

$$\Sigma\frac{1}{nlnnlnlnn}$$

from n=27 to n=10^(100,000)

is approximately equal to 8.1

Related Calculus and Beyond Homework Help News on Phys.org
i did the u substitution, u =nlnn

and i get

$$\int\frac{1du}{u}$$

which just becomes [lnu]
which becomes: [ln(lnlnn)] evaluated from 27 to 10^100,000

exk
is the denominator of your summation n*ln(n)*ln(ln(n))?

yea it is