Stress in rope with pulley and weight

Click For Summary

Homework Help Overview

The discussion revolves around calculating the stress in a fishing line connected to a pulley system with weights added incrementally. The original poster is working with the formula for stress, having calculated the force exerted by the weights and is seeking assistance with determining the cross-sectional area of the fishing line.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the cross-sectional area of the fishing line and question the necessity of multiplying this area by the length of the line. There is an exploration of the implications of the calculated stress values and their comparison to atmospheric pressure.

Discussion Status

Participants are actively engaging with the problem, providing insights and corrections regarding the calculations. Some guidance has been offered on the correct approach to calculating stress and the relevance of Young's modulus in this context. Multiple interpretations of the problem are being explored.

Contextual Notes

There is mention of the specific dimensions of the fishing line and the incremental weights being used, as well as the potential for large stress values resulting from the calculations. The discussion reflects uncertainty about the correct application of formulas and the physical meaning of the results.

Dearster
Messages
4
Reaction score
0

Homework Statement



Im trying to work out the stress of a fishing line after connecting a fishing line to a pulleyboard and adding 100g weights one at a time onto the fishing line to create strain and stress.

I know the formula is Stress = Force divided by area

And i have already worked out the force acting on the fishing line for each 100 gram weights which are added. If i have done this right it is 0.1 (100 g) multiplied by 9.81 (gravity) to give 0.981.

Also i have the diameter of the fishing line as 35 microns (3.5 x 10 to the power of -5)

So the area of the cross section of the circular fishing line is needed and then needs to be multiplied by the length of the fishing line which is 1.2 metres.

Can anyone help me out with this please?

Thank you so much

Homework Equations



Stress = Force / Area

Area of circular fishing line = pie x radius squared x length of fishing line (1.2 metres)

The Attempt at a Solution



I keep on getting a 8 billion pascals answer :S
 
Physics news on Phys.org
So the area of the cross section of the circular fishing line is needed
Yes.

and then needs to be multiplied by the length of the fishing line which is 1.2 metres.
No. Why multiply by the length. Area * length = volume.

Take the force 0.981 N and divide by the area pi*d2/4 m2.

1.02 E9 Pa. or 1.02 GPa

Compare to 1 atm = 0.101325 MPa. So this is about 10000 atm of pressure/stress or 147 ksi (for a 100 g load), which is a rather large stress.
 
Last edited:
So would that surfice to go on and work out the young modulus of that fishing line seeing as i already have the strains?

I thought you may have had to work out the cross sectional area of the fishing line and multiply by the length to find the entire area of the fishing line, but i think you may be right.And thank you so much :)
 
35 microns is thin.

That is 1.38 mil or 0.00138 inch.

For tensile stress, one is interested in the load (force) divided by the cross-sectional area.

Young's modulus has units of stress, since strain is dimensionless.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
8K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
6K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K