Strong Duality Theorem in Linear Programming

math8
Messages
143
Reaction score
0
If a linear Program (P) has a feasible solution x_{o}, ( x_{o} not necessarily optimal),does it follow that there exists a feasible solution to the dual problem (D) as well? If yes, why?

I know that the Strong Duality Theorem guarantees an optimal finite solution to the dual problem if the primal problem has an optimal finite solution. But I cannot see why this would be the case if the feasible solution to the primal is not necessarily optimal.
 
Physics news on Phys.org
math8 said:
If a linear Program (P) has a feasible solution x_{o}, ( x_{o} not necessarily optimal),does it follow that there exists a feasible solution to the dual problem (D) as well? If yes, why?

I know that the Strong Duality Theorem guarantees an optimal finite solution to the dual problem if the primal problem has an optimal finite solution. But I cannot see why this would be the case if the feasible solution to the primal is not necessarily optimal.

If P is the primal and D is the dual, the possibilities are: (i) P and D are both feasible (in which case they both have finite optimal solutions with equal objectives); (ii) P is feasible and D is infeasible (in which case P has no finite optimum); (iii) D is feasible and P is infeasible (in which case D has no finite optimum); (iv) both P and D are infeasible.

RGV
 
Thanks :). That helps!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top