- #1

Flucky

- 95

- 1

I'm having a bit of a brain block with this equation (it's the very end of a problem).

N([itex]\frac{5}{6}[/itex])[itex]^{N-1}[/itex] > [itex]\frac{27}{5}[/itex]

My line of thought was to get the first N in terms of the power N-1..

How do I find N?