Stuck on an equation involving powers - I only have 1 unknown

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Homework Help Overview

The discussion revolves around an inequality involving a variable \( N \) in the context of a problem related to the rolls of a dice. The original poster expresses difficulty in simplifying the inequality \( N\left(\frac{5}{6}\right)^{N-1} > \frac{27}{5} \) to isolate \( N \).

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the possibility of simplifying the inequality and question whether the coefficient \( N \) is the same as the exponent \( N \). There are suggestions to graph the equation or use trial and error to find suitable values for \( N \).

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the use of graphical methods and numerical approaches, but there is no explicit consensus on how to proceed analytically.

Contextual Notes

There is a mention of the problem being related to rolls of a dice, and the original poster indicates a potential need to post the full question in a different subforum for further assistance.

Flucky
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Hi all sorry the title couldn't be more descriptive.

I'm having a bit of a brain block with this equation (it's the very end of a problem).

N([itex]\frac{5}{6}[/itex])[itex]^{N-1}[/itex] > [itex]\frac{27}{5}[/itex]

My line of thought was to get the first N in terms of the power N-1..

How do I find N?
 
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Analytically you can't.
 
Sorry I meant how do I simplify the inequality, ie N > #
 
What dirk_mec1 said.

However, a comment in the OP raises a question: is the coefficient N the same variable as the exponent N? You seem to imply that they are different.
 
Ah I guess I've gone wrong somewhere.

Yes the N's are the same.
 
Is ##N## supposed to be an integer?
 
It represents the rolls of a dice. I'm going to post the full question over in the physics homework subforum.
 
Flucky said:
It represents the rolls of a dice. I'm going to post the full question over in the physics homework subforum.

Then it suffices to solve it by trial and error. An easy method is to graph the equation ##y=x\left(\frac{5}{6}\right)^{x-1}## with a calculator. That way the value(s) of ##N## that satisfy the OP will become clear. Once you found a suitable candidate for ##N##, you can rigorously prove that this ##N## is a good candidate by just plugging it in the equation and calculating manually.

There is no way to solve the equation analytically, so you will need to resort to trickery such as the above.
 
  • #10
Flucky said:
Thanks but I have probably just messed up somewhere, as I don't think it will be that much hassle.

https://www.physicsforums.com/showthread.php?p=4716123#post4716123

Actually, if the problem is truly as given in the above link then the solution will involve even more hassle that what you have now. Why would you think the solution is "easy"? What do you have against plotting graphs or against using numerical methods?
 

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