Sum of Infinite Series: -3^(n-1)/(8^n) with Geometric Form and Scalar Value

In summary, the conversation discusses finding the sum of a series and suggests using the formula for a geometric series. The individual is struggling with manipulating the given series to fit into the correct format, but suggests splitting the fraction into two parts to make it easier to solve.
  • #1
brusier
27
0

Homework Statement



Find the sum of the following series.

SUM (n=1 to inf) -3^(n-1)/(8^n)

Homework Equations



Possibly fit into ar^n format?


3. The Attempt at a Solution [/b

I feel there is a way that this fits into a geometric form in which case could use a/(1-r) to find the infinite sum. I'm having trouble manipulating to fit into ar^n format when there are a couple powers of n in the general form.
Can the scalar 'a' value have an exponent in it? I guess not then it would be an exponential not a scalar
 
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  • #2
Your notation is ambiguous: do you mean [tex]\sum_{n=1}^\infty -\frac{3^{n-1}}{8^n}[/tex] or [tex]\sum_{n=1}^\infty \frac{(-3)^{n-1}}{8^n}[/tex] ?

Either way, you should try to find a way to split this fraction into [tex]\left(\frac{a}{b}\right) \cdot \left(\frac{c}{d}\right)^n[/tex]. Then you will be able to apply the formula for the sum of a geometric series. You have the right idea; you just need to get the manipulations right.
 

Related to Sum of Infinite Series: -3^(n-1)/(8^n) with Geometric Form and Scalar Value

1. What is the formula for finding the sum of an infinite geometric series?

The formula for finding the sum of an infinite geometric series is S = a/(1-r), where a is the first term and r is the common ratio.

2. How do you determine if a series is convergent or divergent?

A geometric series is convergent if the absolute value of the common ratio (r) is less than 1. If the absolute value of r is greater than or equal to 1, then the series is divergent.

3. Can you simplify the given series using the formula for the sum of an infinite geometric series?

Yes, the given series -3^(n-1)/(8^n) can be simplified to -1/11 using the formula S = a/(1-r), with a = -3/8 and r = -1/8.

4. Is the sum of an infinite geometric series always a finite value?

No, the sum of an infinite geometric series can be a finite value if the series is convergent. However, if the series is divergent, the sum will be infinite.

5. How is the sum of an infinite geometric series related to the concept of limits in calculus?

The sum of an infinite geometric series is closely related to the concept of limits in calculus. As the number of terms in the series increases towards infinity, the sum approaches a certain value, which is the limit of the series. This value can be calculated using the formula for the sum of an infinite geometric series.

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