Sum of Infinite Series: -3^(n-1)/(8^n) with Geometric Form and Scalar Value

Click For Summary
SUMMARY

The series SUM (n=1 to inf) -3^(n-1)/(8^n) can be expressed in geometric form to find its sum. The correct approach involves manipulating the series into the format ar^n, where 'a' represents the initial term and 'r' the common ratio. The formula for the sum of an infinite geometric series, S = a/(1-r), is applicable once the series is correctly formatted. The discussion emphasizes the importance of correctly interpreting the notation and splitting the fraction to facilitate the application of the geometric series formula.

PREREQUISITES
  • Understanding of geometric series and their properties
  • Familiarity with series notation and manipulation
  • Knowledge of the formula for the sum of an infinite geometric series
  • Basic algebraic skills for fraction manipulation
NEXT STEPS
  • Learn how to manipulate series into the ar^n format
  • Study the derivation and application of the infinite geometric series formula
  • Explore examples of series convergence and divergence
  • Investigate the role of scalar values in series and their implications
USEFUL FOR

Students studying calculus, mathematicians interested in series convergence, and educators teaching geometric series concepts.

brusier
Messages
27
Reaction score
0

Homework Statement



Find the sum of the following series.

SUM (n=1 to inf) -3^(n-1)/(8^n)

Homework Equations



Possibly fit into ar^n format?


3. The Attempt at a Solution [/b

I feel there is a way that this fits into a geometric form in which case could use a/(1-r) to find the infinite sum. I'm having trouble manipulating to fit into ar^n format when there are a couple powers of n in the general form.
Can the scalar 'a' value have an exponent in it? I guess not then it would be an exponential not a scalar
 
Physics news on Phys.org
Your notation is ambiguous: do you mean [tex]\sum_{n=1}^\infty -\frac{3^{n-1}}{8^n}[/tex] or [tex]\sum_{n=1}^\infty \frac{(-3)^{n-1}}{8^n}[/tex] ?

Either way, you should try to find a way to split this fraction into [tex]\left(\frac{a}{b}\right) \cdot \left(\frac{c}{d}\right)^n[/tex]. Then you will be able to apply the formula for the sum of a geometric series. You have the right idea; you just need to get the manipulations right.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
2K
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K