Sum of Sequence: Find the Solution | Homework Help

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Homework Help Overview

The discussion revolves around finding the sum of a geometric sequence defined by the terms: 2, -2/3, 2/9, -2/27, 2/81, and so forth. Participants explore the properties of geometric series and the appropriate formulas for calculating the sum.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the common ratio of -1/3 and express uncertainty about applying the correct formula for the sum of the series. There are mentions of using the formula for the sum of a geometric series and considerations of whether it applies to an infinite series.

Discussion Status

Some participants have provided guidance on using the geometric series sum formula, while others are verifying their calculations and discussing the implications of the series being infinite. There is acknowledgment of different interpretations regarding the application of formulas.

Contextual Notes

There is a focus on ensuring proper notation in mathematical expressions, and some participants reflect on their habits in writing formulas. The discussion includes an exploration of the first term and the common ratio in the context of an infinite series.

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Homework Statement



Find the sum of the sequence:
2, -2/3, 2/9, -2/27, 2/81, . . .

Homework Equations





The Attempt at a Solution



I can see that the number is multiplied by -1/3, but I'm unsure of how to find the sum.

Any pointers?
 
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use the formula for the sum of geometric sequence.
 
nicnicman said:

Homework Statement



Find the sum of the sequence:
2, -2/3, 2/9, -2/27, 2/81, . . .

Homework Equations





The Attempt at a Solution



I can see that the number is multiplied by -1/3, but I'm unsure of how to find the sum.

Any pointers?

This is a geometric sequence. There's a formula for finding the sum of a geometric series.
 
an+1-1/a-1
 
Summed over n: [itex]\sum[/itex]ak=an+1-1/a-1
 
FeynmanIsCool said:
an+1-1/a-1
Use parentheses!

What you wrote is an + 1 - (1/a) - 1
FeynmanIsCool said:
Summed over n: [itex]\sum[/itex]ak=an+1-1/a-1
 
haha good note, your right. I have bad habits when it comes to those things
 
Thanks for the help!

I came up with 1 41/81 using the formula. This also equals the sum of the numbers in the sequence (in my original post).

So, I guess it's correct.
 
Although, this is in infinite geometric set so should I be using this formula:

S∞ = a1/(1-r), where a1 = the first term in the sequence, and r is the ratio.
 
Last edited:
  • #10
So the answer would be 1 1/2. Correct?
 
  • #11
nicnicman said:
So the answer would be 1 1/2. Correct?

Yes, it's 3/2.
 
  • #12
Thanks for the reassurance.
 

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