Sum Real x: Solving ((2^x)-4)^3 + ((4^x)-2)^3

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The discussion focuses on solving the equation ((2^x)-4)^3 + ((4^x)-2)^3 = ((4^x)+(2^3)-6)^3. Participants explore algebraic identities related to sums of cubes but find the left-hand side challenging due to its complexity. There is a suggestion to simplify the equation by expressing all terms in powers of 2. The conversation emphasizes the need for a strategic approach to manipulate the equation effectively. Overall, the thread seeks guidance on how to initiate the solution process for the given problem.
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Homework Statement



Find the sum of all real x such that

((2^x)-4)^3 + ((4^x)-2)^3=((4^x)+(2^3)-6)^3


Homework Equations


Nil



The Attempt at a Solution



(a-b)^3+3ab(a-b)=a^3-b^3

This equation doesn't help as the LHS is a sum of two cubes.

Is it wise to convert all fours and sixes as multiples of 2?

Please help me to get a start at least.
 
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It is also true that a^3+ b^3= (a+ b)(a^2- ab+ b^2).
 
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