whats the summation of a^n for a>1 over summation n=0 to N thanks.
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Sep 10, 2012 #2 DonAntonio 606 1 amaresh92 said: whats the summation of a^n for a>1 over summation n=0 to N thanks. Hint: for [itex]\,r\neq 1\,[/itex] a constant, we have $$\sum_{n=0}^mr^n=\frac{r^{m+1}-1}{r-1}$$ DonAntonio
amaresh92 said: whats the summation of a^n for a>1 over summation n=0 to N thanks. Hint: for [itex]\,r\neq 1\,[/itex] a constant, we have $$\sum_{n=0}^mr^n=\frac{r^{m+1}-1}{r-1}$$ DonAntonio
Sep 10, 2012 #3 Simon Bridge Science Advisor Homework Helper 17,857 1,655 This is the sort of thing most people just look that up - do you need to work out the formula or what?
This is the sort of thing most people just look that up - do you need to work out the formula or what?