1. Sep 10, 2012 #1

   amaresh92

   

   whats the summation of a^n for a>1 over summation n=0 to N
   thanks.

    

   amaresh92, Sep 10, 2012
2. 
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3. Sep 10, 2012 #2

   DonAntonio

   

   Hint: for [itex]\,r\neq 1\,[/itex] a constant, we have
   
   $$\sum_{n=0}^mr^n=\frac{r^{m+1}-1}{r-1}$$
   
   DonAntonio

    

   DonAntonio, Sep 10, 2012
4. Sep 10, 2012 #3

   Simon Bridge

   

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   This is the sort of thing most people just look that up - do you need to work out the formula or what?

    

   Simon Bridge, Sep 10, 2012

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