Summation inside a summation inside a summation

  • #1
qwerty12345
5
0
IMG_20120915_210615.jpg



I know how to do it normally, but this confuses me. Can you show me how to do it? And what were the steps you took... etc. Initially, I thought of putting them inside brtackets and work out the last one at the right first, but I'd need to know what K and J are, it's confusing. Can anyone make this clear for me?



EDIT:
IMG_20120915_222841.jpg


I tried this, but it doesn't seem like I'm on the right track.
 
Last edited:

Answers and Replies

  • #2
qwerty12345
5
0
IMG_20120915_230928.jpg


But I also solved it with a calculator and it says the answer is 81. What am I doing wrong?
 
  • #3
qwerty12345
5
0
Nevermind. I figured it out. :D

IMG_20120915_232603.jpg
 
  • #4
SammyS
Staff Emeritus
Science Advisor
Homework Helper
Gold Member
11,687
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1-1+1 = 1 not -1 ... that's if you mean i - j + k and not i - (j + k) .
 

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