Summing a Geometric Series: Can We Use the Formula 1/(1-x)?

Mathman23
Messages
248
Reaction score
0
Hi

Can I claim that in order to find the sum of the series:

\sum_{n = 0} ^{\infty} 2^{- n}

\sum_{n = 0} ^{\infty} 2^{- n} = \sum_{n = 0} ^{\infty} x^n = \frac{1}{1-x} ?


Sincerely Yours
Fred
 
Last edited:
Physics news on Phys.org
No, you can't claim *that* (since it is false; one side is a number, the other is a power series in x), but you can use the series if you do so legitimately.
 
In other words, since 2-n= (2-1)n, yes, if x= 2-1. (Assuming, of course, that the sum converges. Can you show that?)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top