Superconductor in an external magnetic field

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Homework Help Overview

The discussion revolves around a superconducting spherical shell placed in a uniform magnetic field, focusing on determining the magnetic field outside the shell and the surface current density. The problem involves concepts from electromagnetism and superconductivity.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the boundary conditions at the surface of the shell and the implications for the magnetic field and surface current density. There is a focus on the relationship between the magnetic moment and the surface current, with some questioning the validity of certain calculations and the approach taken to express the magnetic moment.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and questioning the methods used. Some guidance has been offered regarding the relationship between the magnetic moment and the surface current, but no consensus has been reached on the best approach to find the surface current density.

Contextual Notes

Participants reference a textbook for additional context, indicating that there may be specific methods or examples that are relevant to the problem at hand. There is an acknowledgment of the complexity involved in relating the magnetic moment to the surface current density.

Raihan amin
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Homework Statement


A superconducting spherical shell of radius R is placed in a uniform magnetic field ##\vec{B_0}##
1)Find the magnetic field everywhere outside the shell
2)the sutface current density

Homework Equations


Inside the shell the net magnetic field is 0, and at the surface also.
The magnetic field of a magnetic diople of moment ##\vec{m}## is
$$\vec{B_m}=\frac{μ_0}{4\pi}[\frac{3(\vec{m}.\vec{r})\vec{r}}{r^5} - \frac{\vec{m}}{r^3}]$$

The Attempt at a Solution



The boundary condition at the surface which is at an angle ##\theta## with the vertical is
$$\vec{B_{0,\hat{n}}}+\vec{B_{m,\hat{n}}}=0$$
So,$$B_0\cos{\theta}+\frac{μ_0}{4\pi}(\frac{2m\cos{\theta}}{R^3} )=0$$
Therefore at $$\vec{m}=-(\frac{2\pi}{μ_0})R^3 \vec{B_0} $$,the boundary condition are satisfied on the surface of the shell.Hence,$$\vec{B}=\vec{B_0}-\frac{(3R^3)(\vec{B_0}.\vec{r})\vec{r}}{2r^5} + \vec{B_0}(\frac{R^3}{2r^3})$$
But i can't find the surface current density in this way. In my textbook,the author has written that we can find that using tangential B's continuity though i didn't get that.
 
Last edited:
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You calculated m as function of B and then plugged in m as function of B again (and I'm a bit surprised the terms don't cancel). You need m as function of the rotation of the surface current.
 
mfb said:
You calculated m as function of B and then plugged in m as function of B again (and I'm a bit surprised the terms don't cancel). You need m as function of the rotation of the surface current.
I know that way,but it is also a valid process i think.
You can see page 305 of "A Guide to Physics Problems" by Cahn and Nadgorny
 
Here it is
 

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