Superposition and electronic circuits

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SUMMARY

The discussion focuses on calculating the voltage across points BD in an electronic circuit using superposition principles. The user successfully determined a source current of 10.08mA and a voltage drop of 2.02V across a 200-ohm resistor. Key advice includes shorting current sources and opening voltage sources to simplify the analysis. The voltage across BD is expressed as the sum of the voltage across a 300-ohm resistor and an additional 3.71V, emphasizing the application of Kirchhoff's Voltage Law (KVL).

PREREQUISITES
  • Understanding of superposition theorem in circuit analysis
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Basic knowledge of voltage and current sources
  • Ability to analyze resistive circuits with Ohm's Law
NEXT STEPS
  • Study the superposition theorem in electrical circuits
  • Learn how to apply Kirchhoff's Voltage Law (KVL) in complex circuits
  • Explore techniques for simplifying circuits by shorting and opening sources
  • Review calculations involving resistors in series and parallel configurations
USEFUL FOR

Students studying electrical engineering, circuit designers, and anyone looking to enhance their understanding of voltage calculations in electronic circuits.

Kobayashi
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Homework Statement


Can someone please explain to me how to find the voltage across BD in the attached circuit. I can't do these examples. Please help.


Homework Equations





The Attempt at a Solution


When I shorted one source I get the source current as 10.08mA and a voltage drop across the 200 ohm resistor of 2.02V.
 

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I think your drawing is missing the current source? Be that as it may, REMEMBER: SHORT current sources and OPEN voltages sources. Do that, give us a complete drawing and show your work and we can help you if needed.
 
Ok, assuming that the circuit is correct, V_BD= V acrosss 300ohms + 3.71V. You need to find that voltage by using KVL.

Hope that helps.
 

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