(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

There are three point particles in fixed positions in an xy plane. Particle A lies at the origin and particle B lies 150 degrees from positive A (reference is positive x axis). The distance between P_{a}and P_{b}is .5m. The mass of P_{a}is 6.00g and the mass of P_{b}is 12.0g. The position of the third particle C is not known but the mass is 8.00g. The net forces acting on particle A (only gravataional) magnittude is 2.77*10^{-14}at an angle of -163.8 degrees. Find the x and y coordiantes of particle C

2. Relevant equations

Need the gravatational force equation F_{g}= Gm_{1}m_{2}/r^{2}

3. The attempt at a solution

This problem is straight forward. Knowing that the force from particle B on particle A plus the coresponding force from particle C must equal the resulting force. So to solve I will break it up into x and y componenet and find the quadanents. So i am working along with the following

F_{net on particle A}cos(-163.8) = F_{gravity AB}cos(150) + F_{gravity AC}COS(theta)

So I subtract the first term on the right from the one on the left. And here is where things go to hell. I have some x component of a force. on the left. I have on the right two unknowns I do not know the distance between A and C, and I do not know x position of particle see which i want to know. I am stuck on how to proceed. I am sure this becomes a pythagorean thing but not sure. Any help much appreciated.

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# Homework Help: Superposition Gravataional Forces

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