Superposition of Gravitational Forces

AI Thread Summary
To find the acceleration of a particle released between a 7.0 kg and a 17 kg mass, the gravitational forces acting on it must be calculated using the formula F_g = (G*m_1*m_2)/r^2. The particle is positioned 0.2 m from the 7.0 kg mass and 0.3 m from the 17 kg mass, leading to two distinct gravitational forces acting on it. The gravitational force from the 7.0 kg mass is calculated first, followed by the force from the 17 kg mass. The net force on the particle will determine its acceleration, which can be found by summing the forces and applying Newton's second law. The focus should remain on the forces exerted by the two fixed masses on the particle, as the fixed nature of the outer masses simplifies the analysis.
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Homework Statement


a 7.0 kg point mass and a 17 kg point mass are held in place 0.5m apart. A particle of mass (m) is released from a point between the two masses 0.2m from the 7.0kg mass along the line connecting the two fixed masses. Find the magnitude and direction of the acceleration of the particle.

Homework Equations


F_g= (Gm_1 m_2)/r^2


The Attempt at a Solution


The force between the two distant masses: (G*7kg*17kg) / (0.5m)2
I know that these two distant masses exert an equal and opposite gravitational force on one another, but I don't know how to relate this force to the force exerted on the point mass in between them.
 
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You write,

"The force between the two distant masses: (G*7kg*17kg) / (0.5m)2
I know that these two distant masses exert an equal and opposite gravitational force on one another, but I don't know how to relate this force to the force exerted on the point mass in between them."

You need not be concerned with the force between the outer masses, we are told they are fixed in place so they don't move. You only want to know the forces on the central mass due to the 7 and 17Kg masses. Use the formula you listed.
 
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