Suppose in general a pair of functions

Flyboy27
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Suppose in general that we have two functions

<br /> <br /> F(x)= \int_{0}^{cos x}e^{xt^2} dt<br />
<br /> G(x)= \int_{0}^{cos x}\(t^2e^{xt^2} dt<br />
<br /> H(x) = G(x) - F&#039;(x)<br />

Where, I need to prove that
<br /> H(\frac{\pi}{4}) = e^\frac{\pi}{8}/\sqrt{2}<br />

Okay, so far I have computed the integrals of both of these functions, where I am confused is when computing F&#039;(x) do I differentiate the integrand with respect to x only, and then simply subtract the two functions. Sorry for the edit, I left off the dt for both integrals. Any help would be appreciated!
 
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Flyboy27 said:
Suppose in general that we have two functions

<br /> <br /> F(x)= \int_{0}^{cos x}e^{xt^2} <br />
<br /> G(x)= \int_{0}^{cos x}\(t^2e^{xt^2} <br />

These integrals are a bit confusing. Are they supposed to be, for example:
F(x)= \int_{0}^{cos x}e^{xt^2} dt

Or something different?
 
Yes I corrected the original post, sorry I left off the dt for both integrals.
 
To find the derivative, with respect to x, of F(x)= \int_{0}^{cos x}e^{xt^2}dt, use "LaGrange's Formula" \frac{d\int_{a(x)}^{b(x)} f(x,t)dt}{dx}= \int_{a(x)}^{b(x)} \frac{\partial f(x,t)}{\partial x} dt+ F(b(x))\frac{db}{dx}- F(a(x)\frac{da}{dx}[/itex].
 
You did mean Leibniz' formula, HallsofIvy?
 
I am always making that mistake. Do you suppose I could convince them to swap names?
 
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