Surface area of a sphere problem

AI Thread Summary
The discussion revolves around calculating the surface area and volume ratios of two spheres, where the radius of sphere 2 is four times that of sphere 1. The surface area formula, 4πR², indicates that the ratio of the surface areas A2/A1 is 16, since the radius affects the area quadratically. For the volumes, using the formula V = 4/3πR³, the ratio V2/V1 is determined to be 64 due to the cubic relationship of the radius. The calculations confirm that the surface area and volume ratios are 16 and 64, respectively. These findings illustrate the significant impact of radius changes on both surface area and volume in spherical geometry.
devildog6289
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Sphere 1 has surface area A1 and volume V1, and shere 2 has surface area A2 and volume V2.
If the radius of shere 2 is four times the radius of shere 1, what is the ratio A2/A1 of the areas?
 
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Surface area of a sphere is 4 Pi R^2 and R2 = 4R1
 
thank you
and i have 1 more question,
what is the ratio V2/V1 of the volumes?
 
devildog6289 said:
thank you
and i have 1 more question,
what is the ratio V2/V1 of the volumes?



V1= 4/3 Π R1^3

V2= 4/3 Π R2^3

Π= PI

DIVIDE BOTH EQUATIONS:

V1= 4/3 Π R1^3
V2= 4/3 Π R2^3

SINCE: R2= 4R1 THEN

V1= 4/3 Π R1^3
V2= 4/3 Π (4R1)^3

V1= 4/3 Π R1^3
V2= 4/3 Π*64*R1^3

CANCEL (4/3, PI & R1^3)

THEREFORE:

V1= 1_
V2= 64

OR V2/V1= 64
 
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