In solving a flux integral over a flat surface, inclined above the xy-plane, does the boundary of the surface influence the flux only through the integral limits? (and not through its normal vector)(adsbygoogle = window.adsbygoogle || []).push({});

Let's say that there is an elliptic surface inclined above the xy-plane. The orientation is given by the plane: z=3-y. Now, when I am supposed to solve this surface integral, it seems I can easily use the normal vector of the plane z=3-y in the dSconversion:

dS= [-(∂f/∂x)[itex]^{2}[/itex], -(∂f/∂y)[itex]^{2}[/itex], 1]dA, where f(x,y)=3-y

This means that I do not need to think about the parametrization of the elliptic surface...

This would ofcourse only be true for flat surfaces. So, for clarification, am I doing something wrong?

**Physics Forums | Science Articles, Homework Help, Discussion**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Surface Integral, flux. Boundary and orientation

**Physics Forums | Science Articles, Homework Help, Discussion**