Surface Integral of a Sphere (non-divergence)

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Homework Help Overview

The discussion revolves around evaluating a surface integral over a sphere defined by the equation x² + y² + z² = 9, with the constraint that z ≥ 0. The integrand is given as G = z.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to parameterize the sphere and compute the differential area element dA using the cross product of the parameterization derivatives. There is uncertainty about the correctness of this approach and the next steps, particularly regarding the use of the dot product.

Discussion Status

Some participants provide guidance on calculating dA more simply and clarify that the dot product mentioned by the original poster is not applicable in this context. There is acknowledgment of the radius being 3, and one participant expresses gratitude for the assistance, suggesting progress in understanding.

Contextual Notes

Participants discuss the use of spherical coordinates and the implications of integrating over a surface without considering the volume element. There is a focus on ensuring the correct interpretation of the mathematical operations involved.

Wildcat04
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Homework Statement



Evaluate: \int\intG(r)dA

Where G = z
S: x2 + y2 + z2 = 9 z \geq 0

Homework Equations



Parameterization
x = r sinu cosv
y = r sinu sin v
z = r cos u


The Attempt at a Solution




r(u,v) = (r sinu cosv)i + (r sinu sinv)j + (r cosu)k
ru = (r cosu cosv)i + (-r cos u sinv)j + (-r sinu)k
rv = (-r sinu sinv)i + (r sinu cosv)j + 0k

dA = |ru x rv|

I am not sure if I am approaching this correctly or if I am way off base. My next step was to complete the dot product of z with dA but this does not seem right and I can't find any good examples in my text.

Thank you in advance.
 
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You are doing it ok. There's a simpler way to get dA. You know that dV in spherical coordinates is just r^2*sin(u)*du*dv*dr, right? dA over a sphere is just that without the dr. But you should get the same thing by finding the norm of your cross product.
 
Last edited:
r= 3 in this problem and you don't use "the dot product of z with dA" because neither is a vector! Just multiply and integrate.
 
Thank you very much for the help! I believe that I have figured it out now.
 

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