Surjectivity and linear maps question

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In my head this proof seems obvious, but I am unable to write it rigorously. :cry: Any help would be appreciated!

Prove that it T is a linear map from F^4 to F^2 such that

kernel T ={(x1, x2, x3, x4) belonging to F^4 | x1 = 5x2 and x3 = 7x4}, then T is surjective.
 
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What's the dimension of the image? (think in terms of the dimension of the domain and the dimension of the kernel)
 
the dimension of the kernel is two, the dimension of the range is two

so F^2 equals dim range and therefore is surjective?
 
dimension of kernel equal 2. Dimension of range equals 2.

dimension of domain equals 4. Since dim range = 2 and F^2 is the whole space of the range, then it is surjective?
 
dyanmcc said:
F^2 equals dim range and therefore is surjective?

F^2 is a vector space, so it can't equal a dimension.

The image is a 2-d subspace of a 2-d space, so it is all of it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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