Surviving a Freefall: Calculating the Impulse on a Paratrooper Landing in Snow

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The discussion focuses on calculating the minimum depth of snow required to safely stop a paratrooper who fell from 370 m and landed at terminal velocity. The paratrooper's mass is 80 kg, and the force from the snow is at the survivable limit of 1.2 x 10^5 N. Participants emphasize the importance of finding the kinetic energy at impact and relate it to impulse and momentum change. The calculations involve using the change in kinetic energy to determine the necessary displacement in the snow. Overall, the thread highlights the connection between kinetic energy, impulse, and safe landing dynamics.
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Homework Statement



In February 1955, a paratrooper fell 370 m from an airplane without being able to open his chute but happened to land in snow, suffering only minor injuries. Assume that his speed at impact was 60 m/s (terminal speed), that his mass (including gear) was 80 kg, and that the force on him from the snow was at the survivable limit of 1.2*10^5 N.

(a) What is the minimum depth of snow that would have stopped him safely?

(b) What is the magnitude of the impulse on him from the snow?

Homework Equations



delta P = F*t
F=ma?

The Attempt at a Solution



I have no clue, I've never seen a problem like this before...
 
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Paratrooper's mass and treminal velocity is given. Find his KE when he touches the ground. Finally he stops. Change in KE = Force X Displacement.
 
I found KE, but what does that have to do with impulse? I thought impulse was change in momentum?
 
impulse is mV1-mV2
 
but KE will tell u what velocity the man lands at the snow
 
mv1 - mv2...is that like P1 - P2? (P stands for momentum)
 
Yes. Now that you have kinetic energy, you have everything you need to solve this.
 
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