Switching between distance variables in a simple seismograph

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The discussion centers on understanding the substitution of variables in a seismograph problem from a textbook. The highlighted portion in the problem involves replacing the y variable with x, which is clarified through figures 3.2.5 and 3.6.3. The equations derived from Newton's second law illustrate how the substitutions simplify the original equation, ultimately leading to a more manageable form. The key takeaway is that these substitutions are meant to facilitate solving the problem by achieving equilibrium. The participants agree that the textbook provides the necessary context for these transformations.
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Below is an example problem from my textbook. I don't fathom the highlighted portion where they replace the y variable with x in accordance with fig. 3.6.3?

Please help

Thanks

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Doesn't figure 3.2.5 explain it?
 
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paisiello2 said:
Doesn't figure 3.2.5 explain it?

Here is the other Figure. Unfortunately, I still don't fathom??
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In figure 3.2.5 they are simply substituting in X'e to simplify the equation. From Newton's 2nd law of motion:
∑F = m⋅d2X/dt2
m⋅d2X/dt2 = mg - k(X - Xe) ...(Eq. 1)

At equilibrium we know that ∑F = 0, therefore:
mg - k(X - Xe) = 0
→ X - Xe = mg / k ...(Eq. 2)

Making the following two substitutions into (Eq. 1):
Xe = X'e - mg/k
X = X'e + x
→ m⋅d2(X'e + x)/dt2 = mg - k((X'e + x) - (X'e - mg/k))
→ m⋅d2(x)/dt2 = mg - kx + mg
→ m⋅d2x/dt2 = kx ...(Eq. 3)

Now Eq.3 is simpler than Eq. 1, agreed?

I assume your textbook already has all this.
 
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