Switching between distance variables in a simple seismograph

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Below is an example problem from my textbook. I don't fathom the highlighted portion where they replace the y variable with x in accordance with fig. 3.6.3?

Please help

Thanks

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Doesn't figure 3.2.5 explain it?
 
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paisiello2 said:
Doesn't figure 3.2.5 explain it?

Here is the other Figure. Unfortunately, I still don't fathom??
image.jpg
 
In figure 3.2.5 they are simply substituting in X'e to simplify the equation. From Newton's 2nd law of motion:
∑F = m⋅d2X/dt2
m⋅d2X/dt2 = mg - k(X - Xe) ...(Eq. 1)

At equilibrium we know that ∑F = 0, therefore:
mg - k(X - Xe) = 0
→ X - Xe = mg / k ...(Eq. 2)

Making the following two substitutions into (Eq. 1):
Xe = X'e - mg/k
X = X'e + x
→ m⋅d2(X'e + x)/dt2 = mg - k((X'e + x) - (X'e - mg/k))
→ m⋅d2(x)/dt2 = mg - kx + mg
→ m⋅d2x/dt2 = kx ...(Eq. 3)

Now Eq.3 is simpler than Eq. 1, agreed?

I assume your textbook already has all this.
 
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