"Switching Transistor" OFF Impedance

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Discussion Overview

The discussion revolves around the impedance characteristics of a Bipolar Junction Transistor (BJT) when it is in the "OFF" state, particularly in the context of using the transistor as a switch for a stepper motor. Participants are exploring the expected impedance values and the implications of circuit design choices on the performance of the transistor.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Experimental/applied

Main Points Raised

  • One participant notes that the measured Emitter-Collector impedance is 470 Ohms when the BJT is "OFF," which is lower than expected for a switching transistor.
  • Another participant suggests checking the datasheet for specifications and inquires about the presence of a pull-down resistor in the circuit.
  • A participant describes the circuit configuration, indicating that the microcontroller signal may be causing the transistor to draw current even when it is supposed to be "OFF."
  • There is a suggestion to use a 1K resistor between the Base of the BJT and Ground to prevent floating conditions that could lead to leakage current.
  • One participant raises a question about the behavior of the transistor, suggesting that a positive signal at the input would bias the transistor "ON," likening it to a common-emitter amplifier.
  • Another participant emphasizes the importance of considering ideal conditions in switching circuits and questions the implications of fast switching on the MOSFET controlling the motor.
  • A request for clarification on which NMOS transistor is being used is made, indicating a need for specific details regarding the components involved.
  • There is a discussion about whether the observed behavior of the circuit has been consistent or if it is a new issue, with a participant expressing that an "OFF" transistor should present a higher impedance than observed.

Areas of Agreement / Disagreement

Participants express differing views on the expected impedance of the BJT when "OFF," and there is no consensus on the best approach to mitigate the current draw in the circuit. The discussion remains unresolved regarding the optimal configuration and component choices.

Contextual Notes

Participants mention potential issues with floating signals and the implications of circuit design on transistor behavior, but these points remain unresolved and depend on specific circuit configurations and component characteristics.

sandy.bridge
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Hey all,

When a Bipolar Junction Transistor is "OFF" (i.e., Vb = 0), what are typical Emitter-Collector impedances? We are using a switching BJT as a switch for a stepper motor, however, we have just realized that the impedance is rather low when the transistor is off (470 Ohms). I would have expected this to be much larger for a transistor that is built for switching.
 
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The datasheet should list some of this - however how are you switching it "off" - do you have a pull down resistor?
 
We are sending it a signal from a microcontroller. Attached you will see a portion of the circuit. The problem is that when the bases are "low", or even floating, the circuit is drawing current.
 

Attachments

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I would use a 1K (?) resistor between the Base of Q1 and Ground. When the uC is Low, it is probably more like "floating" and the Q1 becomes a Voltage divider - allowing some leakage current - This also seems to be reverse logic ( when the uC is Low(Q1 off) the Motor is ON because the Gate of M1 gets Pulled up ) - is this what you want?
 
Wouldn't a positive signal at the input of Q1 cause a current to flow into the base and thus bias Q1 "ON"? This is merely a common-emitter amplifier, no?
 

Attachments

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Wouldn't a positive signal at the input of Q1 cause a current to flow into the base and thus bias Q1 "ON"? This is merely a common-emitter amplifier, no

yes and that turns M1 ( the FET) off

As windact said its kinda reverse logic
 
In a switching circuit - think of ideals -- perfect switch.. If Q1 is "on" - ideally - what is the V at M1s Gate ... and conversely - if Q1 is "off" -- ideally -- what is the V at G-M1?

Your number 2 diagram --- is not the same as your #1 diagram...redraw #2 - in the arrangement of #1 and then add the parts that are missing.

As a matter of design best practices - the MOSFET is VERY FAST - what happens if the motor is running ( current flowing) any you "try" to turn it OFF VERY FAST??
 
Which particular NMOS transistor are you using?
 
sandy.bridge said:
We are sending it a signal from a microcontroller. Attached you will see a portion of the circuit. The problem is that when the bases are "low", or even floating, the circuit is drawing current.
You believe it has always behaved like this, or are you investigating now only because something has recently stopped working properly?

Or is this a new circuit that isn't yet working how you want it to? Certainly, an OFF transistor should present more than a few kΩ to low voltage DC.
 
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