- #1

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(a) (1-i)z + 4w = 2 + 8i

(b) 3z + (1+i)w = 1 + 5i

I tried expanding but that didn't get me anywhere. Then i put it in a matrix, but i didn't know how to go from there. Any suggestions? Thanks.

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- #1

- 43

- 0

(a) (1-i)z + 4w = 2 + 8i

(b) 3z + (1+i)w = 1 + 5i

I tried expanding but that didn't get me anywhere. Then i put it in a matrix, but i didn't know how to go from there. Any suggestions? Thanks.

- #2

arildno

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You should then have 3z in both equations.

2. Then subtract the first from the second and solve for w.

3) Don't bother to expand brackets until you've solved for w and z

- #3

Hurkyl

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For instance, in the first equation, the coefficient on z is simply the (single!) number (1 - i). So, if when solving systems of equations, you like to divide through by the leading coefficient, then you would do so, by dividing through by (1 - i).

- #4

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thanks guys...i think i got it...

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