- #1
Haynes Kwon
Gold Member
- 21
- 0
Since F=Δp/Δt...
Δp=mΔv+vΔm, Δm=0
Δp=mΔv
Therefore, Δp/Δt=mΔv/Δt=ma.
And if I multiply 'r' to both sides
rF=rma, which is τ=rma
My question is: is 'a' centripetal acceleration or is it tangential acceleration?
If 'a' is centripetal acceleration, which is v^2/r, τ=rmv^2/r=mv^2?
Also I don't really get what tangential acceleration is...
Δp=mΔv+vΔm, Δm=0
Δp=mΔv
Therefore, Δp/Δt=mΔv/Δt=ma.
And if I multiply 'r' to both sides
rF=rma, which is τ=rma
My question is: is 'a' centripetal acceleration or is it tangential acceleration?
If 'a' is centripetal acceleration, which is v^2/r, τ=rmv^2/r=mv^2?
Also I don't really get what tangential acceleration is...