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Take the derivative respect to U

  1. Aug 19, 2009 #1
    V = [tex]\sqrt{T/u}[/tex]

    Take the derivative respect to U. I'm having trouble with this.

    [tex]\sqrt{T}[/tex] * 1/[tex]\sqrt{u}[/tex]


    So would u look like this U^-(1/2)

    since T is constant I'd leave it alone.

    it would become -(1/2) * u^(-3/2)


    Am I right or Am I wrong.
     
    Last edited: Aug 19, 2009
  2. jcsd
  3. Aug 19, 2009 #2
    Re: Derivatives.

    Right now you can re-write the equation as V= T^(1/2)*u^(-1/2)
    effectively this is in the form of y=c*x^n (just to go back to familiar notation)
    what is the generic formula for this? Your close, but your leaving out the constant...

    So what would the answer be once you include it?
     
  4. Aug 20, 2009 #3
    Re: Derivatives.

    V= T^(1/2)*-(1/2) * u^(-3/2)
     
  5. Aug 20, 2009 #4
    Re: Derivatives.

    looks pretty good to me!
     
  6. Aug 21, 2009 #5
    Re: Derivatives.

    since T is a constant your answer is right
     
  7. Aug 23, 2009 #6
    Re: Derivatives.

    Thanks for the assistance!!!!
     
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