# Homework Help: Take the derivative respect to U

1. Aug 19, 2009

### afcwestwarrior

V = $$\sqrt{T/u}$$

Take the derivative respect to U. I'm having trouble with this.

$$\sqrt{T}$$ * 1/$$\sqrt{u}$$

So would u look like this U^-(1/2)

since T is constant I'd leave it alone.

it would become -(1/2) * u^(-3/2)

Am I right or Am I wrong.

Last edited: Aug 19, 2009
2. Aug 19, 2009

### n1person

Re: Derivatives.

Right now you can re-write the equation as V= T^(1/2)*u^(-1/2)
effectively this is in the form of y=c*x^n (just to go back to familiar notation)
what is the generic formula for this? Your close, but your leaving out the constant...

So what would the answer be once you include it?

3. Aug 20, 2009

### afcwestwarrior

Re: Derivatives.

V= T^(1/2)*-(1/2) * u^(-3/2)

4. Aug 20, 2009

### n1person

Re: Derivatives.

looks pretty good to me!

5. Aug 21, 2009

### hangover

Re: Derivatives.