Tangent at self-intersection point

  • Thread starter Thread starter TPAINE
  • Start date Start date
  • Tags Tags
    Point Tangent
TPAINE
Messages
21
Reaction score
0

Homework Statement



Find the slopes of the two tangent lines of x^3-y^2+x^2=0 at 0,0.

Homework Equations


Differentiating implicitly we get (dy(x))/(dx) = (x (2+3 x))/(2 y).


The Attempt at a Solution


I'm not sure how to deal with the derivative being undefined at 0,0 when there are clearly two tangent lines.
 
Physics news on Phys.org
Try solving the equation for y and differentiate each branch explicitly.
 
I'm aware it can be done that way. However, is there a way to do it without separating the curve into branches, for equations where that is not so easy (or impossible)?
 
Good question. In the situation where you can't write an explicit formula for the function I don't think there is any guarantee you can do it. I could be wrong, but I don't think so.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top