Tarzan vine Conservation of Energy

AI Thread Summary
The discussion focuses on a physics problem involving Tarzan swinging on a vine across a gorge, emphasizing the conservation of energy principles. The key equations used are potential energy (PE = mgh) and kinetic energy (KE = 1/2mv^2). The challenge lies in determining the height 'h' to calculate Tarzan's velocity 'v' at the moment he jumps onto the vine. A solution approach involves using trigonometry to find the hypotenuse of a right triangle formed by the vine and the gorge, allowing for the calculation of the maximum height reached. The method successfully applies energy conservation principles to solve the problem.
bmarvs04
Messages
12
Reaction score
0

Homework Statement



A 17 meter long vine hangs vertically from a tree on one side of a 10 meter wide gorge, as shown in the figure. Tarzan runs up, hoping to grab the vine, swing over the gorge, and drop vertically off the vine to land on the other side

Homework Equations



PE = mgh
KE = 1/2mv^2

The Attempt at a Solution



Since energy has to be conserved, I tried setting to two equations equal to each other. In other words, the kinetic energy he had as he jumped onto the rope, and the potential energy he has at the top of his swing when he isn't moving.

I got stuck because I can't find 'h', therefore I can't find 'v'

Thanks in advance
 
Physics news on Phys.org
use right angle triangle to find hypoteneuse using 17 and 10 as the sides.
Then calculate the angle (so between the ground and the rope = between side length 10 and the hypoteneuse) using trig.
You can subtract the length of the hypoteneuse by the length of the rope, then use that length with the calculated angle to get the max height- 'h' reached by using trig.
Then apply energy conservation.
 
Thanks a bunch.. It worked perfectly
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top